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Find the equation of the tangent plane to the hyperboloid f(x,y,z)=x^2/a^2 +y^2/b^2 -z^2/c^2 =1 at (x_0,y_0,z_0 )
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Take the gradient which gives you a vector perpendicular to the surface. Evaluate it at (x_0,y_0,z_0) and you'll have a normal vector. From there you need to evaluate: \[\hat{n} \cdot (\vec{r} - (x_0,y_0,z_0))=0\] And this will give you the equation of the plane.
The gradient is defined as: \[\vec{\nabla}f(x_1,…,x_n)=\sum_{k=1}^n \frac{\partial f}{\partial x_k}\vec{e}_k\] where e_k is the unit vector in the kth direction.
i have already calculate it..can you please check it.
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