This is a really easy question, please! The first one to explain it to me and give me the right answer gets a medal. PLEASE HELP SOON!! ~ ~ Samuel is researching the favorite foods of the students in his grade. He surveys the students in his science class. Which of the following is not true?
Here is the question.
Did it specify he used stratified sampling?
He didn't use stratified sampling. To use a stratified sample, you would take, for example, one student from each class in the grade and give them the survey.
A significant fact.
lol thanks I got it... but now I have a new question ad;lfjadslkjfa;sdlfj @douglaswinslowcooper @applemuffin95
Where's your Q?
Here. @douglaswinslowcooper
@douglaswinslowcooper The one that is blue and bubbled in is the one I think. I think that's a spinner because their spinners have like, 10 things on it. But a deck of cards have 4 suits. A die has 6 sides. Slips of paper? lol
You want simulations that easily work with probability of 1 chance in 4. For example, the deck of cards could have each suit correspond to a gumball flavor. Two of the other three could be made to work. the third would be awkward. Do you see which one?
The spinner? @douglaswinslowcooper
Spinner could have 4, 8, 12, 16 locations, and so might work. Lots of slips of paper could be used, with a fourth of them the target flavor. How would a die or dice work?
Spinner, perhaps. Die, certainly.
OOOhhhh so the answer is a die... @douglaswinslowcooper lol now there is a graph I need help with omg seriously I did all the essays and stuff on my own, and it's 11:16. Can you help too?
I'm hooked. I'll try.
haha omg thank you so much. here it is, I'm working on it. you can help too. @douglaswinslowcooper
@douglaswinslowcooper
lol I was good with everything else in the module. The only thing that I couldn't do was probability... This part of the test is about probability. ( / )_( \ ) @douglaswinslowcooper
lol there is another matching thing after this... I think only 1 though. :) I answered like, 3 questions. whoop whoop @douglaswinslowcooper
noooo omg where did you goooooo I need your help like, really bad. O.O @douglaswinslowcooper
Fine. We have D M F S, as Darnell, Mother, Father, Sister Without replacement means there are three choices left after the first pick. With replacement means there are four choices again. Note that "parent" means either M or F, an added complication. P(D and S), with replacement First pick: could get D or S out of the group of four, so p1=2/4 Second pick, must get the other one (D if have S. S if have D), so p2=1/4 Joint probability: p1*p2 = 2/16 = 1/8 = .125 My problem is that none of your choices include 1/8, so I'm off or they are. I'll try another.
if it is soooo simple....
P(M and F, without replacement): First pick, p1=2/4 as either M or F ok Second pick, p2=1/3, as three are left, one either M or F not gotten before. Joint probability = p1*p2 = 1/12 , one of your choices
P(parent and sister, without replacement 1st pick M or F: p1 = 1/2 2nd pick, have one parent, D, S left, thus p2 = 1/3 Joint p1*p2= 1/6
P(parent and child, with replacement): 1st pick M or F out of four: p1 = 2/4 2nd pick D or S out of four: p2 = 2/4 joint = p1*p2 = 4/16 = 1/4
omg thank you so much, you don't know how much this means. @douglaswinslowcooper
okay, ummm... I think I only have one more question... lemme check. @douglaswinslowcooper
uhh I have one more graph... that's it I think. @douglaswinslowcooper
are you up to it? @douglaswinslowcooper
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