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Mathematics 17 Online
OpenStudy (anonymous):

Differentiate logarithmically: y = (sinx)^(2x) y= sinx to the power of 2x

OpenStudy (anonymous):

\[y = (sinx)^{2x}\]

OpenStudy (sheraz12345):

apply ln on both sides

OpenStudy (anonymous):

\[y=\left( \sin x \right)^{2x},\ln y=2x \ln \sin x\]

OpenStudy (anonymous):

yep, and then differentiate

OpenStudy (anonymous):

and then solve for y'

OpenStudy (sheraz12345):

yes. Now differentiate

OpenStudy (anonymous):

Oh thank you guys, I see were I was messing up. Thank you!!!!!!!!

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