Question

What are the zeroes of the function?
$$y = (x + 3)(x +2)(x – 2)$$
I have expanded the function to:
$$y = x^3+3 x^2-4 x-12$$

I really do not know what else to do?

Answer 1

Don't expand it. Look at the factors

Answer 2

Now answer me one question first, if A*B=0, A and B can be what?

Answer 3

Well one of the variables will have to be zero?

Answer 4

exactly, so when (x-3)(x+2)(x-2)=0, what can (x-3), (x+2) or (x-2) be?

Answer 5

$$x = –3, –2, 2$$

Answer 6

exactly

Answer 7

That was relatively simple,
Thank you :-).

Answer 8

De nada :D