Divide these two fractions
\[\frac{ 2x }{ x+4 } \div \frac{ 6 }{ x+3 }\]
K so reverse and multiply, Ist step 2x x+3 ---- x ----- x+4 6
like cross multiply them
?
Can u multiply from there or do u need more of an understanding? Whenever u divide u always reverse reciprocal or we would just be multiplying ex. (4/2) / (8/2) reverse reciprocal 4/2 x 2/8 = 1 So try to apply this concept to your problem!
Reverse, then if u can cross multiply u do so i reversed them. Yes, u can cross multiply 1st step to reverse 2x x+3 ---- x ----- x+4 6 Second step cross multiply x x+3 --- x ---- x+4 3 Third step multiply straight across: x^2 + 3x -------- 3x+ 12
So do u think we can simplify from here? show me if u think u can!
x^2/12
Yes good so far!
Any further? (If u have learned to square both sides of an equation)
how would i square x^2
What kind of math are you in?
algebra 2 but math has always been my downfall
Because i believe its in algebra II where u learn how to square both sides of an equation, so the answer could be simplified : x^2 to sqrt each side so it undoes the ^2 and then square 12 to 3.5: x/(sqrt)12 x/3.46 or 3.5 rounded but if not then the answer is x^2/12
When i say square each side its misleading by square or undoing ^2 I can further simplify equation instead of leaving it as x^2/12, any Q's?
no no i think im starting to understand it
Want another example or do u have it, happy to help if u need it :)
i got it. thank you so much!
:D glad u got it !
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