Question

I GIVE MEDALS.

A car drives on a circular track with a constant speed of 84 m/s. The track has a radius of 225 m.


What is the centripetal acceleration of the car?

Answer 1

f = mv^2/r

ma = mv^2/r

a = v^2/r

a = 84^2/225

a = 31.36 m/s^2

Answer 2

How would i find the acceleration of the car measured in g? @li_za12

Answer 3

what do u mean Exactly by "acceleration of the car measured in g". do u want to show this acceleartion in terms of g? :S if that so then---
a = v^2/r
a = 31.36 m/s^2
also we know g = 10 m/s^2
a/g = 31.36/10
a = 31.36/10 g m/s^2
a =3.13g m/s^2
Was this ur question? :S

Answer 4

yes, thanks!
How would i figure out what speed would give the car an acceleration of 9.8 m/s2? @CyberShadow

Answer 5

oh that ,
here it is ---
As we know that ,
a = v^2/r
and we want to get an acceleration of a = 9.8 m/s^2
also r = 225 m
therefore
9.8 = v^2/225
implies
v^2 = 9.8 * 225
v = (2205)^1/2
v = 46.9 m/s
get it? :)

Answer 6

That makes so much more sense, haha.
thanks! @CyberShadow

Answer 7

No worries :)