Question

Integral Calculus Question:
Find the area of the region bounded by the graph of the equation

y=x^3 + x, x =2, y = 0

I'm having trouble finding out what the area of the region is because I am only given one x value, or at least I think I am only given one x value.

Answer 1

I think I have figured out that I need to set x^3 + x to 0. That will give me x = 0. Thanks everyone but I will thank anyone who responds to this XD

Answer 2

Yes, just what I was going to advise. y=0 at x =0 provides the closure.

Answer 3

Thanks :)

Answer 4

You are welcome.

Answer 5

Do you have the rest of it OK?

Answer 6

I think so. I'll post a question if I need more help.

Answer 7

Fine. Integral of x^n is [1/(n+1] x^(n+1)