Ok im gonna be asking a lot of questions right now so get ready for medals people who answer in full, here is one... if i can figure out how to put an attachment lol
Select the proper equation in point-slope form for the given point and slope. Point: (–8, 3); Slope: 6 y + 3 = 6x – 48 y + 3 = 6(x + 8) y – 3 = 6(x – 8) y – 3 = 6(x + 8)
Solve y = 6 x + b given y=3 when x = -8 that will give you b
You've got a point, and you've got the slope. The equation for a line passing through a known point \((x_0,y_0)\) with slope \(m\) is \[y-y_0 = m(x-x_0)\] Suppose your point was \((-5,1)\) and your slope was \(3\): \[(x_0,y_0) = (-5,1)\]\[y-1 = 3(x-(-5))\]or\[y-1=3(x+5)\]That's your point-slope equation for the line of slope \(3\) passing through the point \((-5,1)\)
is that all?
That's all you need to do. I did a different point and a different slope, so as not to just give you the answer, but I showed you the procedure to solve this problem.
If it looks really simple, that's because it is :-)
no i meant is that all for like his problems
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