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Can you solve log(4k-5)=log(2k-1)? Also, can you show the steps on how to solve an equation like this? Thanks.
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If \( \log a= \log b\) then \(a = b\).
(4k-5) and (2k-1).
Make them equal and solve for k.
So, it'd be 4k-2k=-1+5?
Correct. Now combine like terms on both sides.
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Is it 3 then? My friend got 2 so i was confused.
Thanks anyways.
Sorry, I lost the connection for a while. I'm back now.
This line is correct. 4k-2k=-1+5 Now subtract 4k - 2k on the left side and add -1 + 5 on the right side: 2k = 4 Finally divide both sides by 2 k = 2
You're friend is correct. The answer is k = 2.
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