An athlete runs from A to B and comes back at a speed of 10 kmph, while a second athlete simultaneously runs from B to A and comes back at a speed of 15 kmph. If they cross each other for the first time in 12 minutes after they start, they will meet each other the second time in
Do you see how to find the distance between A and B?
speed in opposite directionis 10+15=25kmph speed =dist/time, time=d/25
so what's the distance between A and B?
120 km
10*12=120
reasonability check: if they are 120 km apart, are the two guys really going to meet after only 12 minutes of running?!?
dont know
come on, 120 km? do you normally use km or miles?
km
well, you said the speed is 25 km per hour. that means about 5 hours to cover the whole distance...
but these guys are supposed to cover the distance between A and B in 12 minutes!
look, between the 2 of them, they cover 25 km each hour. in 12 minutes (= 1/5 of an hour, because 12/60 = 1/5), they meet up. that means the distance between A and B must be 1/5 of 25 km, no?
10/12=5/6km,15/12=5/3km
5km
right!
second time 10km
how to calculate time then ?is it 24 min
the second meeting isn't quite as easy as that to find... the two runners will cover 10km in 24 minutes, true. but the question is will they be at the same point at that time? at the first meeting: runner 1 will have run 12/60 * 10 = 2 km runner 2 will have run 12/60 * 15 = 3 km |dw:1389252797770:dw|
|dw:1389252867280:dw| After another 12 minutes of running, runner 1 will have run 24/60 * 10 = 4 km and runner 2 will have run 24/60 * 15 = 6 km
That means runner 1 will be almost to B (4/5 of the way there), and runner 2 will have gotten to A and started back to B
they aren't in the same spot, so that isn't where they meet for the 2nd time
what about in another 1/5 hour of running?
after 60 minutes they meet?
after48 minutes
i think after 48 minutes only they meet
becoz a covered 8 km and b covered 12km
am i correct they will meet at 3km
do u understand @whpalmer4
I think they meet again at 3/5 of an hour. runner 1 will have done 3/5 * 10 = 6 km, runner 2 will have done 3/5 * 15 = 9 km. |dw:1389253925336:dw| runner 1 goes from A to B and 1 km back toward A. runner 2 goes from B to A and 4 km back toward B, ending up 1 km away from B, which is where runner 1 is.
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