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Mathematics 16 Online
OpenStudy (anonymous):

please help? Let f(x)={x^2, x<1 ; 2x, x>1 a. find f'(x) for x<1 b. find f'(x) for x>1 c. find lim x→1^- f'(x) d. find lim x→1^+ f'(x)

OpenStudy (anonymous):

Do you need help to find f`(x)? It will have two parts too.

OpenStudy (anonymous):

I can find f'(x)

OpenStudy (anonymous):

What is the problem than?

OpenStudy (anonymous):

the answer not going to be the same for all 4.

OpenStudy (anonymous):

True it will depend where you are :) What is the answer for a, and b, ?

OpenStudy (anonymous):

a) 2x b) 2 c) 2 d)2

OpenStudy (anonymous):

thanks @eliassaab but I need to do work to.

OpenStudy (anonymous):

\[ \lim_{x->1^-} 2 x =2\\ \lim_{x->1^+} 2 =2\\ \]

OpenStudy (anonymous):

@eliassaab do you think you could help with these? e. Does lim x→1 f'(x) exist? Explain/justify your answer. f. Use the definition to find the left-handed derivative of f at x=1 if it exists. g. Use the definition to find the right-handed derivative of f at x=1 if it exists. h. Does f'(1) exist? Explain/justify your answer

OpenStudy (anonymous):

also if it shows im not viewing this question, I am. im on mobile so its weird.

OpenStudy (anonymous):

thank you so much!

OpenStudy (anonymous):

YW

OpenStudy (anonymous):

Wait, I need to do some corrections. Sorry.

OpenStudy (anonymous):

e) yes since the right hand limit and the left hand limit exist and are equal f) yes and it is equal to 2 g) yes and it is equal to 2 h) no because the function f is not continuous at x=1, so it cannot be differentiable at 1

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