1.Graph the system of inequalities. Then use your graph to identify the point that represents a solution to the system. x > 3 y ≤ 2x – 5 (5, 6) (4, –1) (–3, –1) (1, 11) 2. Graph the system of inequalities. Then use your graph to identify the point that represents a solution to the system. x – y ≥ 7 x + 2y < 5 A. (6,1) B. (8,-1) C. (6,2) D. (6,-2) 3. Graph the system of inequalities. Then use your graph to identify the point that represents a solution to the system. 3x – 4y > 0 x – 5y > 0 A. (-4,-2) B. (6,0) C. (0,0) D. (6,2)
The formatting kinda confuses me, sec. Put them into y = mx + b or in this case with an inequality. Then graph them.
On #1, it says x >3 ... are you missing a y?
@Taylor115
No
Hmph, what grade is this? Lets move onto the rest, we'll get back to #1
okay and grade 8th
Hmm, x – y ≥ 7 x + 2y < 5 x – y ≥ 7 -x -x -y ≥ -x + 7 /-1 /-1 /-1 y ≤ x - 7 same as -> y ≤ x/1 -7 .. the slope is 1 and the y intercept is (0,-7) x + 2y < 5 -x -x 2y < -x + 5 /2 /2 /2 y < -x/2 + 2.5 .. the slope is -x/2 (rise/run) and the y intercept is (0,2.5) Now plot them on a graph
if you substitute (0, 0) for x and y, and get a true statement, you must shade on the side that includes the origin.
Okay thank you very much ^-^
Yw, can you continue or do you still need help
I would still like some help please, math is very hard for me.
k
I must warn you, i'm a horrible artist so using a graphing calculator is suggested >.<
lol thats okay
|dw:1389296248638:dw| The solutions lie where they over lap, so by plugging in any pair will give you a true statement
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