how many real number solutions are there to the equation o=-3x^2+x-4???

Question

anonymous · Answer

a) 0
b) 1
C) 2
D)3

anonymous · Answer

Are you familiar with the quadratic formula? I suggest you use this to solve the equation and then simply look at how many roots you've got. Once you've done this, you can go back and think about which part of the equation dictated how many results you got. If you have an idea, perhaps test with some other quadratics.

anonymous · Answer

idk the quadratic formula confuses me so much and i cant figure out how to do it

anonymous · Answer

The solutions of
$$ax^2 + bx + c = 0$$are given by
$$x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$$

anonymous · Answer

Ik, but i dont understand its really confusing on how to set it up

anonymous · Answer

What don't you understand? Where it comes from? Otherwise it's just a matter of substituting coefficients in until you're used to it.

anonymous · Answer

i dont get how to substitute them in

anonymous · Answer

By comparing the ax²+bx+c with the equation you're trying to solve, you can see the values of the coefficients a, b and c which you can then use in the quadratic formula.

anonymous · Answer

but there are more than 3 numbers?

anonymous · Answer

Hm?

anonymous · Answer

nvm