medals given i have a very simple question. f(x) = x^2 is that linear or nonlinear?
It will always be nonlinear unless the x lacks an exponent above 1.
with the x being squared, you get an exponential growing graph.
f(x) = 4x - 1 is that linear @noseboy908
look at what I said before: anytime the x's exponent is NOT above 1, then it's linear. so, what's the exponent on "4x-1"?
it would be linear!
indeed.
any more?
yessss lollll y=3x-1 ?
ok, so look at what I said earlier. what's the exponent on the x here?
the x is before the 1 right ?
yes, but that doesn't matter.
so the answer is not linear ?
I'm afraid you're incorrect. look at the x. does it have any shown exponents?
no the x does not have any exponets i got a little confused sorry.
it's ok, just slow down. SO, if the x doesn't't appear to have any exponents, then we can always assume that it's to the power of one. And now, given the rule stated above, is it linear or non?
we can assume that it not linear rght ?
Write a paragraph describing how you found the function rule for the relation. Include whether or not the function is linear or nonlinear and how you know. If this pattern were to continue, what would function- y = 3x-1 i need help i know its linear but how did you get it ?
wait, back to your second to latest reply, why do you think that? the x's exponent is 1, is it not?
ok, reading your most recent reply, I know because the x's exponent is assumed to be one. and whenever it's one, it's linear.
okay i understand now you hekoed a lot with that i dont get these linear nonlinear things
Don't worry too much about nonlinear equations for now, you (as I understand it) just have to be able to tell if they're linear or not. For now, be happy you're only identifying. So, do you understand how to distinguish the two?
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