Question

finding the distance between (-4,2) and (4,-13)

Answer 1

the distance between \(-4\) and \(4\) is \(8\) units along the \(x\) axis
the distance between \(2\) and \(-13\) is \(15\) units in the \(y\) direction
by pythagoras, the distance between the points is
\[d=\sqrt{8^2+15^2}\] whatever that is

Answer 2

you can also you
\[d=\sqrt{x_2-x_1)^2+(y_2-y_1)^2}\] which amounts to the same thing

Answer 3

ok great how would you find the mid point of that

Answer 4

take the average in each coordinate

Answer 5

i.e. add them up and divide by 2