Ask your own question, for FREE!
Mathematics 13 Online
OpenStudy (anonymous):

Simplify log2 1/2

OpenStudy (anonymous):

Do anyone know how to do this?

OpenStudy (mathmale):

What I'd recommend would be that you re-write that 1/2 as a power of 2: 1/2 = 2^(-1).

OpenStudy (anonymous):

solve \[2^x=\frac{1}{2}\] for \(x\)

OpenStudy (mathmale):

Copy the original problem and substitute 2^(-1) for that 1/2. Does this make the problem solution any more obvious for you? Satellite's approach is perfectly good also.

OpenStudy (anonymous):

\[\log_b(x)=y\iff b^y=x\] you should be able to switch back and forth quickly, that is how you do most of these

OpenStudy (anonymous):

I got -1 as the answer

OpenStudy (mathmale):

Cool!! Congrats!

OpenStudy (mathmale):

Are you a Pretty 1?

OpenStudy (anonymous):

Yay

OpenStudy (mathmale):

:)

OpenStudy (anonymous):

@mathmale Thanks!

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!