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Simplify log2 1/2
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Do anyone know how to do this?
What I'd recommend would be that you re-write that 1/2 as a power of 2: 1/2 = 2^(-1).
solve \[2^x=\frac{1}{2}\] for \(x\)
Copy the original problem and substitute 2^(-1) for that 1/2. Does this make the problem solution any more obvious for you? Satellite's approach is perfectly good also.
\[\log_b(x)=y\iff b^y=x\] you should be able to switch back and forth quickly, that is how you do most of these
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I got -1 as the answer
Cool!! Congrats!
Are you a Pretty 1?
Yay
:)
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@mathmale Thanks!
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