Cardon Form Help The bonds of these atoms are strong and produce a solid which is extremely hard and unreactive. A) diamond B) graphite C) fullerene D) nanotube 2. In this type of bond, the carbon atoms are bonded tightly within the layers. However, the structure is very weak because of the different layers. What bond does this describe? A) graphite B) diamond C) nanotube D) fullerene Please help me :D thank you
if anyone knows i would love you :D these are the two i just dont know i thought maybe the first one is diamond but i dont know
i think it is graphite.
for the first or second one?
for the first question.
Strengh of material depends on the energy of the bonds. 1) Single bonds = most stable. Pi bonds or double bonds is more reactive, or higher in energy, etc. It also depends on how well the atomic orbitals overlaps, or the shapes/arrangements of the atoms in the crystals. Those with a higher degree of strain have higher energies. However, certain molecules are stable due to electronic structure such as resonance from pi-orbital conjugation. An example is fullerene or nanotubes. I would say diamond is the most stable, since it has single bonds. Forgot what graphite was. However, you can eliminate fullerene and nanotubes because they have C=C double bonds, which is more reactive than C-C single bonds. We also know for sure diamond is harder than graphite.
the first one is obviously diamond, \(sp^3\) hybridized (tetrahedral arrangement) and, essentially, one molecules. the second is graphite, it's made up of a 2 dimensional bonding arrangement ("sheets") of highly conjugated \(sp^2\) carbon atoms that are held together via london dispersion intermolecular forces of \(\pi\) electrons. graphite is pencil lead, btw.
very informative :)
thanks :)
good job i learned alot from you guys. :)
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