Simplify the expression. quantity cosecant of y plus cotangent of y times quantity cosecant of y minus cotangent of y divided by cosecant of y.
Do you know how to translate this into mathematical symbols?
plz start by writing them out in equation form
no I don't how do I do that on here?
u can type it like cos(y) n such...
plus means + minus means - divided by means /
Be sure to put the top of that division in ( ) and also the bottom in ( )
(csc(y)+cot(y))(csc(y)-cot(y))/(csc(y))
does (cscy+coty) and (cscy-coty) cancel out and leave me with the denominator?
Multiply the top out. (a+b)(a-b)=a^2-b^2
(csc(y)^2)-(cot(y)^2)
good. now you should realize you could use a Pythagorean identity here
\[\ \text{ Recall } 1+\cot^2(y)=\csc^2(y)\]
yes csc2 θ = cot^2 θ=1
I think you mean + not = between the cot^2(theta) and 1 part.
whoops +1 not -1 so the cot^2 y's both cancel out and leave me with 1?
yes I did mean to put the + there instead
yes so that would mean we have 1 on top
and csc(y) on the bottom?
we have that on bottom yes
what is the reciprocal of csc(y)?
ohhhhh i see so the final answer is sin(y)?
yep
awesome! would you mind helping me with one or two more?
one more
(cos^2θ)/(sin^2θ) +cscθ sinθ
so remember csc(theta) is the reciprocal of sin(theta) so csc(theta)*sin(theta)=?
1?
yep
now for the cos/sin part
cos/sin equals what trig function?
cot(y)
and yes since we have those items were squared then we have cot^2(y)
so we have cot^2(y)+1
refer back to that Pythagorean identity
and that is equal to csc^2θ
yep
thank you so much. I have a question for you- is ap stat anything like pre calculus? because I want to take that class next year but I am not that good at precalc
is ap stat a college thing? there could be some calculus in some initial stat courses but i think a lot of calculus occurs in deeper statistics
it is but at my high school i can take it as a senior. and okay that is really good to know. So there is a chance that someone could really stink at calculus but be good at ap stat. because I have always been very good at math but precalc is just not my forte
You should ask the teacher who will be teaching that course. I'm no way familiar with your course information at your school.
okay thank you for the help on the problems and the information!! You are amazing!
Glad I can help.
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