Mathematics
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OpenStudy (anonymous):
Please help with this Trig Simplify Question.
Simplify (tan x/sin x)+(1/cos x).
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OpenStudy (potatoes.ramu):
Write tanx in terms of sin and cos
OpenStudy (anonymous):
more like\[\frac{ tanx }{ sinx }+ \frac{ 1 }{ cosx }\]
what is \[tanx \] in terms of sinx and cosx?
OpenStudy (potatoes.ramu):
So.. tanx=sinx/cosx
OpenStudy (potatoes.ramu):
tanx=sinx/cosx
OpenStudy (potatoes.ramu):
Substitute that value of tanx in the above equation :)
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OpenStudy (anonymous):
hi @Potatoes.ramu . Please, you may continue.
OpenStudy (potatoes.ramu):
@Shanaronan try it and tell me what you get :)
OpenStudy (anonymous):
I've got 2tanx as my simplified equation.
OpenStudy (potatoes.ramu):
No no that's wrong.. The whole point is to eliminate tanx
OpenStudy (potatoes.ramu):
So substitute sinx/cosx in place of tanx and tell me what you get :)
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OpenStudy (anonymous):
2sin/cosx?
OpenStudy (potatoes.ramu):
See
(sinx/cosx)/sinx
OpenStudy (potatoes.ramu):
So you get 1/cosx in the first half
OpenStudy (potatoes.ramu):
So totally 1/cosx+ 1/cosx
OpenStudy (anonymous):
So thats 2/cosx right? Sorry I'm terrible with trig, I cant seem to transfer what I know about regular math to the identities and whatnot.
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OpenStudy (potatoes.ramu):
No worries! It gets easier the more you practice :)
OpenStudy (potatoes.ramu):
So don't fret :)
OpenStudy (potatoes.ramu):
Just remember the basic identities, that's all you need :)
OpenStudy (anonymous):
Okay, thanks ^^
OpenStudy (potatoes.ramu):
No problem :)