Ask your own question, for FREE!
Mathematics 17 Online
OpenStudy (anonymous):

Please help with this Trig Simplify Question. Simplify (tan x/sin x)+(1/cos x).

OpenStudy (potatoes.ramu):

Write tanx in terms of sin and cos

OpenStudy (anonymous):

more like\[\frac{ tanx }{ sinx }+ \frac{ 1 }{ cosx }\] what is \[tanx \] in terms of sinx and cosx?

OpenStudy (potatoes.ramu):

So.. tanx=sinx/cosx

OpenStudy (potatoes.ramu):

tanx=sinx/cosx

OpenStudy (potatoes.ramu):

Substitute that value of tanx in the above equation :)

OpenStudy (anonymous):

hi @Potatoes.ramu . Please, you may continue.

OpenStudy (potatoes.ramu):

@Shanaronan try it and tell me what you get :)

OpenStudy (anonymous):

I've got 2tanx as my simplified equation.

OpenStudy (potatoes.ramu):

No no that's wrong.. The whole point is to eliminate tanx

OpenStudy (potatoes.ramu):

So substitute sinx/cosx in place of tanx and tell me what you get :)

OpenStudy (anonymous):

2sin/cosx?

OpenStudy (potatoes.ramu):

See (sinx/cosx)/sinx

OpenStudy (potatoes.ramu):

So you get 1/cosx in the first half

OpenStudy (potatoes.ramu):

So totally 1/cosx+ 1/cosx

OpenStudy (anonymous):

So thats 2/cosx right? Sorry I'm terrible with trig, I cant seem to transfer what I know about regular math to the identities and whatnot.

OpenStudy (potatoes.ramu):

No worries! It gets easier the more you practice :)

OpenStudy (potatoes.ramu):

So don't fret :)

OpenStudy (potatoes.ramu):

Just remember the basic identities, that's all you need :)

OpenStudy (anonymous):

Okay, thanks ^^

OpenStudy (potatoes.ramu):

No problem :)

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!