Question

state amplitude period and phase shift for the function (once again ie browser plz wait for attachment)

Answer 1

$$
f(x)=A\sin(\cfrac{2\pi}{T}+\phi)
$$
A is amplitude
\(T\) is period
\(\phi\) is phase

Now just match each of these up with \(your\) equation.

Answer 2

f(x)=3sin(2theta+pi)
so amplitude is 3, phase is pi and what is the period?

Answer 3

@ybarrap

Answer 4

I assume that there is a typo in the question because f(x) has no x in the sinusoid, so I'm taking \(x=\theta\) as the variable.
$$
f(\theta)=A\sin(\cfrac{2\pi}{T}\theta+\phi)
$$
With \(\theta\) as the variable, so
$$
2=\cfrac{2\pi}{T}\\
\implies T=\pi
$$

If we don't assume that \(\theta\) is the variable, then there would be no period.

Answer 5

but my values for phase and amplitude are correct?

Answer 6

@ybarrap

Answer 7

yes