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(x^2-3x)/(x^2-9)
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Nice name. So do you know how to factor the difference of two squares?
That, combined with factoring an x out of the numerator, you should see something nice pop out at you...
I got 3x/9 as the answer. It seems this is incorrect
Nope. You'll have to factor the top and bottom so that each has a binomial in common that you can divide out.
Pretty straightforward. Factor, they simplify.\[\frac{x^2-3x}{x^2-9}=\frac{x(x+3)}{(x-3)(x+3)}=\frac{x}{x-3}\]Do math every day.
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I see , very concise. Use the force wisely my friend
That's no fun unless you're forced to work for it.
Actually Animal Ain is wrong haha the bottom is x+3
Yep. Hate it when that happens.
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