Question

The range of the function y = secx - 2 is all reals except

-3 12 years ago

Answer 1

y = cos(x) [-1,1]
y = sec(x) \((−\infty,−1]∪[1,\infty)\)
y = sec(x) - 2 You tell me!

Answer 2

@tkhunny is that a no....?

Answer 3

):

Answer 4

I didn't say that. Why do you doubt. Did you get it or not?

Answer 5

What does sec equate to?

Answer 6

@nelsonjedi 1/cos

Answer 7

Correct..now what is the range for cos?

Answer 8

It doesn't "equal to" anything. It is a function requiring an argument. Generally, we see this definition:

\(\sec(x) = \dfrac{1}{\cos(x)}\)

Answer 9

Please don't EVER write 'sec' or 'cos' in a formula. Just don't do it. You THINK it's a convenient shorthand. It's really just confusing.

Answer 10

@tkhunny oh.... okay! then sec(x)=1/cos(x)
@nelsonjedi (-1,1)!

Answer 11

How do

y = sec(x)
and
y = sec(x) - 2

compare?

The Domain of y = sec(x) is everything Real except (-1,1)
Move that down two.
You had it right. I'm just trying to get you to prove it and be SURE!

Answer 12

@tkhunny oh! hahahaha then my answer if correct?? :D

Answer 13

Yes it is. You DO need to understand why so that you can go confidently forward.