need help on a problem
\[3x - 3 \left| \le \right| 8 \]
@PeytonPerez372 is that an absolute value sign surrounding the less than or equal to sign?
yes it is
sorry i wrote the problem wrong
oh wait… oh okay I was about to say, I don't know how to solve that lol
lol yea let me redo it
sure :)
\[\left| 3x-3 \right| \le 18\]
alright :) so first, you would create two equations \(-3x-3\le18\) \(-3x-3\ge-18\)
does this make sense to you so far?
yes it does
alright… do you know what to do from here or shall i continue? xDD
can you please continue
sure :) so once you have these equations, solve for one variable \(-3x-3\le18\) \(-3x-3\ge-18\) +3 +3 +3 +3 ------------ --------------- \(-3x\le21\) \(-3x\ge-15\) *note: when dividing by a negative, flip the sign*
from here, do you think you can solve for x? for both equations?
@PeytonPerez372 ?
no i need help the rest of the way please
there are my choices for answers.? A. [-18\le x \le18\] B. \[-15 \le x \le21\] C. \[-7 \le x \le 5 \] D\ \[-5 \le x \le 7 \]
okay…so here I left off with: \(-3x\le21\) and \(-3x\ge-15\) /-3 /-3 /-3 /-3 --------- -------------- \(x\ge-7\) \(x\le5\)
so that is what you get after you solve. if x is greater than -7 but less than 5, what will the answer look like? @PeytonPerez372 ?
do you get it? :P
yes mam thank you :)
oh no problem, just wanted to be sure… anytime :D
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