Question

Any help would be greatly appreciated! =) One zero of the function is given. Find all the other zeros. x^3-3x^2-x-12; zero at 4.

Answer 1

@jim_thompson5910

Answer 2

@shrutipande9

Answer 3

Are you familiar with synthetic division?

Answer 4

Yes!

Answer 5

Were you able to get anywhere with synthetic division?

Answer 6

I'm working on it right now!

Answer 7

=)

Answer 8

alright, tell me what you get

Answer 9

I got (x^3-3x^2+9x-37) with a remainder of 136

Answer 10

x = 4 is a zero, so you should have gotten a remainder of 0

Answer 11

Yeah! Sorry I did it wrong! Now I got x^2-7x+27-120/x+4

Is that right?

Answer 12

First write out the coefficients. Then place the root/zero (4) on the left side in its own box