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What is the dy/dx of x^5= -xy^3?
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product rule and chain rule for this one
yeah mate i still don't undestand. i'm a bit lost
start with \[5x^4=-(y^3+3xy^2y')\] and solve for \(y'\)
you are thinking that \(y=f(x)\) even though you have not solved for it visualize it as \[x^5=-xf^3(x)\]
I am coming up with -(6x^4 + y^3)/3xy^2
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\[5x^4=-(y^3+3xy^2y')\] is the first step or \[5x^4=-y^3-3xy^2y'\]
i think you just have a typo there with the \(6\)
otherwise your answer is right
-(5x^4 + y^3)/3xy^2 right?
looks good to me
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