Question

a=bxt+c plz help

Answer 1

what do you need to do with that equation ?

Answer 2

solve for x

Answer 3

the first step will be to take away c from both sides of the equation

Answer 4

how?

Answer 5

a-c=bxt?

Answer 6

yep that right so far

Answer 7

now you want to divide both sides of the equation by b, and by t

Answer 8

ok

Answer 9

a-c/bt=bxt/bt

Answer 10

yeah , you might like some brackets on the left hand side to be clear (a-c)/bt

and the right hand side simplifies

Answer 11

x= (a-c)/bt

Answer 12

wait

Answer 13

you got it!

Answer 14

while your here could you help with one morw

Answer 15

sure

Answer 16

more*

Answer 17

ok

Answer 18

i'll give you a medal after this one

Answer 19

alright the point's are 1,5 and 6,7 and i got 2/5x+y=5 2/5

Answer 20

now i need to find y and x intercepts

Answer 21

i dont think that second point (6,7) is on that line

2/5(6)+(7) = 12/5+7
= (12+35)/5
= 47/5
= 9 2/5
≠ 5 2/5

Answer 22

well i might of made a mistake when doing standard or point slope,or slope intercept this is what i got for a slope 2/5

Answer 23

slope intercept form is y=mx+b

so you just have the sign of the slope the other way around

Answer 24

y=2/5x+?

Answer 25

you had the right intercept before

Answer 26

ok so y=2/5x-5 2/5

Answer 27

almost , now you have the wrong sign on the intercept

Answer 28

?

Answer 29

y = 2/5x+5 2/5

now to check

-2/5x+y = 5 2/5


-2/5(6)+(7) = -12/5+7
= (-12+35)/5
= 23/5
= 5 2/5

Answer 30

and the other point (1,5)

-2/5(1)+(5) = -2/5+5
= (-2+25)/5
= 23/5
= 5 2/5


so both the points are on the line,

y = 2/5x+5 2/5

Answer 31

\[y(x) = \tfrac25x+5\tfrac25\]

the y-intercept is when \(x=0\)
ie at the point \((0,y_0)\),

where \(y_0=y(0)= \tfrac25(0)+5 \tfrac25\)

.

the x-intercept is when \(y=0\)
ie at the point \((x_0,0)\),

where \(y(x_0)=0= \tfrac25(x_0)+5 \tfrac25\)

Answer 32

ok

Answer 33

now i need to find what (x,0) is and (y,0)

Answer 34

i mean (0,y)

Answer 35

yes

Answer 36

so 2/5x+y=5 2/5

Answer 37

i know y is (0,5 2/5)

Answer 38

watch the sign

y = 2/5x+5 2/5

- 2/5x+y =5 2/5

Answer 39

(but yes you have found the y-intercept)

Answer 40

oh i see i added 2/5x to the other side

Answer 41

do i divide or what?

Answer 42

from
y = 2/5x+5 2/5
take 2/5x from both sides to get
- 2/5xy = (2/5x- 2/5x)+5 2/5

- 2/5x+y =5 2/5

Answer 43

ok x=5

Answer 44

wait -x=5
so
-1(-x=5)

Answer 45

- 2/5x+y =5 2/5

Now to get the
x-intercept
just sub y=0

- 2/5x+0 =5 2/5
=
=

Answer 46

(5,0)

Answer 47

now i need to determine if the given point is parallel or perpendicular

Answer 48

can we go a bit quicker i gotta go to school in 15 min