Question

Evaluate summation of negative quantity n minus 5 end quantity from n equals 2 to 8

Answer 1

\[\sum_{n=2}^{8} - (n-5)\]

Answer 2

That sum is probably fastest to just write out and calculate, so put in n=2 plus n=3 plus =4, etc up to 8 and then stop.
So it's just:
\[-(2-5)+(-(3-5))+(-(4-5))+...+(-(8-5))\]

Answer 3

That sum is probably fastest to just write out and calculate, so put in n=2 plus n=3 plus =4, etc up to 8 and then stop. So it's just:
−(2−5)+(−(3−5))+(−(4−5))+...+(−(8−5))

Answer 4

Uhm, you just copied and pasted what @dape wrote

Answer 5

nope

Answer 6

Sure

Answer 7

coucheemma
Medals 0

Sure

a few moments ago