Question

On Monday morning, Colin filled his car with six and one-half gallons of gas, then used three and one-fourth gallons driving. On Tuesday, he used up 2 gallons driving. On Tuesday night, his gas tank had four and one-fourth gallons remaining. How much gas was in Colin's tank before he filled up on Monday morning?

3 gal

three and one-fourth gal

three and one-half gal

three and three-fourths gal

Answer 1

@Compassionate

Answer 2

let x be previous fuel

6 1/2 gallons petrol filled..

3 1/4 + 2 used fuel..

remaining gallons = 4 1/4..

so ,.

x +13/4 = 2 + 9/4 + 13/2

multiply throughout by 4..

4x + 13 = 8 + 9 + 26

4x = 30

x = 30/4 = 7 1/2

Answer 3

but 7 1/2 is not one of the answers am I suppose to divide it or something @Compassionate

Answer 4

What are your answers?

Answer 5

3 gal , 3 1/4 gal, 3 1/2 gal and 3 3/4 gal

Answer 6

Let the amount of gas in the tank before he filled up on Monday be x gallons.
Activity : Amount of gas in tank
Monday morning: x+6.5
Monday driving: x+6.5-3.25=x+3.25
Tuesday driving: x+3.25-2= x+1.25 = Final amount of gas.

Now, use this sentence to form an equation: "On Tuesday night, his gas tank had four and one-fourth gallons remaining"

Answer 7

ok so what does x =

Answer 8

You're basically saying, "please, give me the answer."

Answer 9

no not really

Answer 10

so I just have to solve the last equation right??

Answer 11

\[3\frac{ 1 }{ 2}\]

Answer 12

wow I didn't ask for the answer I asked what equation I would have to solve

Answer 13

I gave you the equation and you ignored it.