Question

Graph the hyperbola with equation
(x+3)^2/4 - (y-3)^2/9 = 1

Answer 1

@agent0smith help :/

Answer 2

Too much effort to graph it by hand...

horizontal hyperbola
center is at (-3, 3)
vertices would be 2 to the left and 2 to the right of the center, so
(-5, 3) and (-1, 3)
and the focus... nobody cares where the focus is.

graph http://www.wolframalpha.com/input/?i=+%28x%2B3%29%5E2%2F4+-+%28y-3%29%5E2%2F9+%3D+1

Answer 3

Okay my thing is how do you know if it is vertical or horizontal

Answer 4

if it's
x^2 - y^2 = 1 it's horiz
y^2 - x^2 = 1 it's vert

So if the x is positive, horiz,
if y is positive, vert
(for hyperbolas)

Answer 5

Oh okay that helps a lot thank you