Question

2x^2+5x-3

Answer 1

I thought it did not exist but I guess I was wrong. I really want to know how to do it.

Answer 2

that would be indeterminate, so you may need to factor then eliminate the common ones

or

you could use l"hospital's rule if you are familiar with it

Answer 3

(x+3)(2x-1)/(x+3)(x-3)

Answer 4

good, now eliminate the like terms

Answer 5

(2x-1)/(x-3)

Answer 6

now you can plug in the limit value of -3 to x

Answer 7

7/6

Answer 8

you got it

Answer 9

Awesome! I got this wrong on one of the tests I had taken and I wanted to know how to do it. :)

Answer 10

it's seems you knew how to do it lol

Answer 11

I guess so. :)