Consider the following sets of numbers. A={all +ve even numbers less than 25} B={all prime numbers less than 25} Suppose a number is chosen at random from 1 to 25. (a) Find P(A), P(B) and P(A∩B). (b) Hence find (AUB). @marigirl
@marigirl is it include 25?
no i will not include 25 .. anyway it wont matter P(A)= total of 12 numbers. therefore if a random number is chosen from 1-25, what will be the probability it will be a even number P(A)=12/25
do u have ans to check
P(A)=12/25
awesome. i checked out and found out there are 9 prime numbers for our given restiction. so what will P(B) be?
1 isn't prime number, is it?
no, 1 is not prime (plus i goggled it :P)
2, 3, 5, 7, 11, 13, 17, 19, 23 is 2 a prime number?
2, 3, 5, 7, 11, 13, 17, 19, 23 yes ur on track
9/25
yes
then P(A∩B)=1/25
2, 3, 4, 5, 6, 7, 8, 10, 11, 12, 13, 14, 16, 17, 18, 19, 20, 22, 23 ,24
sorry for the late reply
I agree with that: then P(A∩B)=1/25
last one Hence find (AUB).
20/25=4/5
P(A U B) = P(A) + P(B)
and minus 1
but it means everything that is in either of the sets
but '2' is repeated
no ur right, sorry
thats why they wrote "Hence" find A U B
anyways i gotta go, well done, you did most of the work!
thank you haha
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