Question

Limits,
http://screencast.com/t/feLljHp8smq

Answer 1

Note:
\[\sin^2(x)=\frac{ 1 }{ 2 }-\frac{ 1 }{ 2 }\cos(2x)\]
(You will need this whenever integrating sin^2(anything).

So let's re-write the integral
\[\frac{ 1 }{ 2 } \int\limits{(1 - \cos (10\theta))} d \theta\]

Then from there...
\[\frac{ 1 }{ 2 }(\theta - \frac{ \sin(10\theta) }{ 10 })+C =\frac{ \theta }{ 2 }-\frac{\sin(10\theta)}{20}+C\]