Question

a person calculated the average of 10"three digit number ".but due to mistake he reversed the digits of a number and thus his average increased by 29.7 the difference between the unit digit and hundreds digit of that number is??

Plz anybody help me out with this qns

Answer 1

hmm, im thinking of something like this to compare with

\[\frac{K+a(100)+b(10)+c}{10}=M+29.7\]
\[\frac{K+a+b(10)+c(100)}{10}=M\]

Answer 2

since b(10) does not change, it can be absorbed into the K with no effect and you are left with a and c to play with

Answer 3

\[100a + c = 10M + 297 - K\]
\[100a + c-297 = 10M - K\]
\[a + 100c = 10M - K\]
....
\[100a+c-297=a + 100c\]

Answer 4

\[99a-297=99c\]
\[99a-99c=297\]
\[99(a-c)=297\]
looks to be something along those lines