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Mathematics 17 Online
OpenStudy (anonymous):

please help! Calculating velocity! picture below!

OpenStudy (anonymous):

OpenStudy (anonymous):

I cant determine where segment A is ending..i know velocity=distance/time though

OpenStudy (anonymous):

@tesla117 can you help at all?

OpenStudy (anonymous):

This type of graph is in a linear format so to calculate the velocity you would do (ending position - starting position) / (ending time - starting time) for the first one (looks like it's 25seconds until it goes flat)... ( 10 meters - 0 meters ) / ( 25 seconds - 0 seconds) = 10/25 = .4 meters/sec The rest I'll leave to you unless you can't figure it.

OpenStudy (anonymous):

Would the velocity for segment B just be 0? since no distance is being covered?

OpenStudy (anonymous):

That is correct I believe the graph was meant to be linear so using the same equation (10m - 10m) / (35-25) = 0/10 and we know zero divided by a number is 0

OpenStudy (anonymous):

okay thank you! and the segmet C would be....30 m/s?

OpenStudy (anonymous):

so plugging the numbers in (30 m - 10 m ) / (60 s -35 s) = (20/25) = .8 m/s

OpenStudy (anonymous):

okay im confused! haha isnt velocity just distance/time?

OpenStudy (anonymous):

what is the whole ending point starting point? i havent learned anything like that! haha just the v=d/t

OpenStudy (anonymous):

Correct think about your response if you where going 30m/s then in the 25 secs you would have traveled over 750 meters! v =d/t is correct and the same thing as the equation I have used but you have to think about it... when you divide each segmanet you get a certain distance which you call "d" which is a real number value say in the section A you d = 10 but to solve for d d = (ending position - starting position) t = (ending time - starting time)

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