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Is my answer right? (calculus)
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\[\int\limits_{1}^{e}4x \ln x dx\] I got 4e-4/x-e/2+9/2
Sorry!! Correct my asnwer to I got 4e-(4/e)-(e/2)+(9/2)
every one here but no one say anything
Did you integrate by parts?
did u integrate that as a indefinite as used some property i used by parts and got the answer as e^2+ 1
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or**
Before you do fundamental thereom of calculus, did you get 4xlnx-(4/x)-(1/x^2). I know I should integrate by parts but by teacher said there was some trick if one of the functions eventually derives down to zero.
\[x²(2\ln x-1)\]
thats what i got after using by parts
and i dont see any complex thing going on here
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Okay, then its probably some algebra error. Thank y'all!
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