Question

integration of sec²(x/2)-1

Answer 1

Any limits? Or is it just an indefinite integral?

Answer 2

no just an indefinite integral

Answer 3

@whpalmer4 @Loser66 c:

Answer 4

\[\int (sec^2(x/2)-1dx=\int sec^2(x/2)dx -\int dx\]
for the second term, it's easy, right? it's = x +C
for the first term , just let u = x/2 du = 1/2 dx or dx = 2du
so, it becomes \[\int 2sec^2u du= 2tanu = 2 tan (x/2)\]
DAT SIT!! don't forget combine 2 terms

Answer 5

thank u

Answer 6

oh, I see you there, but didn't pay attention, I thought you are one of the helper. hehehe. ok, np