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Mathematics 8 Online
OpenStudy (anonymous):

art 1: [4 points] Find the measures of central tendency (mean, median, mode and range) for the following data set: 9, 13, 10, 7, 16, 15, 11 Part 2: [3 points] Tell which of these measures would best represent the whole data set and why.

OpenStudy (mathmale):

I think you should first arrange this data in increasing order, and that you should then actually calculate the mean, median and range and obtain the mode by inspection. Then it will be a bit easier to answer the 2nd part of the question.

OpenStudy (anonymous):

ok i did but i'm still thinking it might be the mean

OpenStudy (anonymous):

or mode

OpenStudy (mathmale):

First, please type out the set of numbers, this time arranged in increasing order. It's important to me that you understand the concepts involved, so I won't be responding as "right!" or "wrong." Want to understand your reasoning.

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

waite

OpenStudy (anonymous):

7,9,10,11,13, 15,16

OpenStudy (mathmale):

Great. Now, how do you define "median?" Explain the process of finding the median when the number of data points happens to be ODD. Then find the median for this set of data.

OpenStudy (anonymous):

the mean is 11.5

OpenStudy (anonymous):

you median is the middle number and it's 11

OpenStudy (anonymous):

the mode is 7

OpenStudy (anonymous):

waite there is no mode

OpenStudy (anonymous):

the range is 7

OpenStudy (mathmale):

Great. Finding the median is a little bit harder when the number of data points is even. But that's another story. Regarding the mean: Have you rounded off your answer? If so, is 11.5 correct to 1 decimal place?

OpenStudy (anonymous):

yes i calculated it to check it

OpenStudy (mathmale):

Wouldn't the mean be 81/7? Do that on your calc.

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

i need help on part two

OpenStudy (mathmale):

I'm being picky here. 81/7=11.5714 should be rounded UP to 11.6, not down to 11.5. Get my drift?

OpenStudy (anonymous):

hmmmm maybe

OpenStudy (anonymous):

let me check

OpenStudy (anonymous):

ok yeah your right oops

OpenStudy (mathmale):

Gotcha.

OpenStudy (mathmale):

OK, now write out the names and the values (if any) of the four measures we've discussed.

OpenStudy (anonymous):

mean: 11.6 Median: 11 mode: there is no mode range: 7

OpenStudy (mathmale):

So that pretty much eliminates both "mode" and "range" as measures of central tendency in this particular problem. Agreed or not?

OpenStudy (anonymous):

agree

OpenStudy (anonymous):

i think it might be the mean and median but how do explain why i think it's that

OpenStudy (mathmale):

So that boils down to mean and median. Which do YOU think best represents the central tendency of this data set?

OpenStudy (anonymous):

ummmm

OpenStudy (anonymous):

the mean

OpenStudy (anonymous):

because..

OpenStudy (anonymous):

i dont how to explain why i think it's that

OpenStudy (mathmale):

What I've done was to actually plot all the data on a number line and then mark the median and mean. One of them appears closer to the "middle" or "center" than does the other. Which one is that?

OpenStudy (anonymous):

median

OpenStudy (mathmale):

I'm treading on marshy ground right now, but my graph of the data shows that 11.5 is closer to the middle of the data set than is the median (11). Again, what do YOU think, and why?

OpenStudy (anonymous):

11.5 would represent the whole data set because it is

OpenStudy (anonymous):

it is closer to middle of the data

OpenStudy (anonymous):

am i right?

OpenStudy (mathmale):

My conclusion would be the same as y ours. Here we're getting down to fine detail. Only you can decide whether or not it's worth the time to delve more deeply into the definitions of mean and median and then again consider which is the better measure of central tendency in this particular statistics problem. Personally, I think you should move on to another problem; you've done very well in this one.

OpenStudy (anonymous):

ok thx

OpenStudy (anonymous):

metal?

OpenStudy (anonymous):

thx

OpenStudy (mathmale):

metal? ??

OpenStudy (anonymous):

yep you get one thx so much i understand

OpenStudy (anonymous):

now

OpenStudy (mathmale):

Oh.... thank you so much!! I do appreciate those medals, but I also get a great deal of satisfaction from this intellectual and social interaction . Best to you. Later, bro.

OpenStudy (mathmale):

Or later, sis.

OpenStudy (anonymous):

lol bye im a girl though

OpenStudy (mathmale):

that's just fine with me! bye!

OpenStudy (anonymous):

bye

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