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Trigonometry
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Prove that: sin^3A+ sin^3(120+A) +sin^3(240+A)= -3/4 sin3A
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Sorry for the late reply: The important thing to note in this question is the simplification part. Expanding sin^3(120+a) and sin^3(240+a) is the worst option. Instead make a simple transformation and you get it in 2 steps. Use the formula sin 3A=3sin A-4sin^3 A From this: sin^3A=(sin3A-3sin A)/-4 -----------(1) Replace all the sin^3 terms in qn by (1) and simply add and you are done! Let me know if you are not still getting it! Good luck!
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