Question

I honestly don't understand this. Multiple choice
graph the logarithmic function
Y= log(x-4)

Answer 1

It'll be the graph of y=log x, but shifted 4 units to the right.

Answer 2

Easiest way to identify it:

y = log x has a vertical asymptote at x=0, since log0 is undefined

y = log (x-4) would have a vertical asymptote at x = ...?

Answer 3

agent0smith definitely has my near-exact words on this

Answer 4

well I think graph 2 on this then.

Answer 5

the one above not the one I just attach lol

Answer 6

To make sure you're correct, check it using a point. Notice the graph above ^^^ passes through (5, 0)

Does the point (5, 0) satisfy this equation?

y = log (x-4)

Answer 7

nope

Answer 8

Are you sure?

What is the vertical asymptote of graph 2?

Answer 9

y = log (x-4)
plug in (5, 0)

0 = log (5-4)
0 = log 1

^^ true or false?

Answer 10

graph 2 is (4,0)

Answer 11

& false

Answer 12

It's true, log 1 = 0, no matter what base.

Think of it as loga 1... what power do you have to raise a, to get 1? 0, since any number to the power of zero, equals 1.


Look for the vertical asymptote before anything else.

y = log (x-4) will have a vertical asymptote when...
x-4 = 0

Answer 13

Oh, right :P

Answer 14

Graph 1's vertical asymptote is x=2

Graph 2's is x=3

Graph 3's is x=4

Answer 15

this is the last graph btw

Answer 16

Graph 4's vertical asymptote is x=-3