Match the correct differential equation to the graph. pls help me check (:
the answer is C. isit?
look at the graph, it has a local maximum in 'first quadrant' that means, y' must have a zero in first quadrant (x>0, y >0)
having figured that out, look at equation A : y' = 1+xy can this guy become 0 ever in first quadrant ? that is when x and y both are positive ?
nope. similarly -2xy can never be 0 in first quadrant.
1-2xy can be 0 in first quadrant : 1-2xy = 0 => xy = 1/2 so oly C can be the potential solution
see if that makes more or less sense hmm
haha so i guessed it right! woo! haha xD i just thought x will most likely be 0.5 in equation c. haha but thanks to the correct explanation(:
yes thats really a good observation ! when x = 0.5 and y = 1, y' = 0 :)
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