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Mathematics 16 Online
OpenStudy (anonymous):

Match the correct differential equation to the graph. pls help me check (:

OpenStudy (anonymous):

OpenStudy (anonymous):

OpenStudy (anonymous):

the answer is C. isit?

ganeshie8 (ganeshie8):

look at the graph, it has a local maximum in 'first quadrant' that means, y' must have a zero in first quadrant (x>0, y >0)

ganeshie8 (ganeshie8):

having figured that out, look at equation A : y' = 1+xy can this guy become 0 ever in first quadrant ? that is when x and y both are positive ?

ganeshie8 (ganeshie8):

nope. similarly -2xy can never be 0 in first quadrant.

ganeshie8 (ganeshie8):

1-2xy can be 0 in first quadrant : 1-2xy = 0 => xy = 1/2 so oly C can be the potential solution

ganeshie8 (ganeshie8):

see if that makes more or less sense hmm

OpenStudy (anonymous):

haha so i guessed it right! woo! haha xD i just thought x will most likely be 0.5 in equation c. haha but thanks to the correct explanation(:

ganeshie8 (ganeshie8):

yes thats really a good observation ! when x = 0.5 and y = 1, y' = 0 :)

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