Question

A line has a slope of –5 and a y-intercept of (0, 3). What is the equation of the line that is perpendicular to the first line and passes through the point (3, 2)?

Answer 1

your first line has a slope of -5. You are looking for a perpendicular line, so you need the negative reciprocal of that slope. All that means is " flip " the slope and change the sign.
So the negative reciprocal of -5, or -5/1, is 1/5 (see how I flipped the slope and changed the sign)

now we will use y = mx + b
slope(m) = 1/5
(3,2) x = 3 and y = 2
we have y and x and m, so we need to find b
now lets sub
2 = 1/5(3) + b
2 = 3/5 + b
2 - 3/5 = b
10/5 - 3/5 = b
7/5 = b

so your perpendicular line is : y = 1/5x + 7/5

Answer 2

thank you!

Answer 3

sure thing :)