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OpenStudy (anonymous):
What is the answer to the following summation
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OpenStudy (anonymous):
\[\sum_{}^{} 2^{p}3^{q}4^{r}5^{s}/(p!q!r!s!)\]
Conditions: p+q+r+s=20
s is a even number
Hint:Use the multinomial theorem
OpenStudy (anonymous):
@LastDayWork @Vincent-Lyon.Fr @oldrin.bataku
OpenStudy (lastdaywork):
Hey, can you upload a snapshot of how the (first) post looks.
OpenStudy (lastdaywork):
Now, even Equation isn't working properly.
OpenStudy (lastdaywork):
^^ @MayankD
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OpenStudy (anonymous):
? I didnt get you!
OpenStudy (lastdaywork):
I can't read your equation. It looks like - \[\sum_{}^{} 2^{p}3^{q}4^{r}5^{s}/(p!q!r!s!)\]
OpenStudy (anonymous):
Yea that is the equation
OpenStudy (anonymous):
*summation
OpenStudy (lastdaywork):
I mean it loos like "sum_{}^{} 2^{p}3^{q}4^{r}5^{s}/(p!q!r!s!)"
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OpenStudy (anonymous):
Okay! Never mind I solved it wgile typing this :P Thanks anyway for responding so fast
OpenStudy (lastdaywork):
:D
OpenStudy (anonymous):
Btw what grade are you in if you don't mind me asking?
OpenStudy (lastdaywork):
Medal Freebies.. :D
OpenStudy (lastdaywork):
I cleared class 12th last year..currently in limbo.. :D
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OpenStudy (anonymous):
Oh okay. I'm a year junior to you then! :P
OpenStudy (lastdaywork):
:)
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