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an=nsin(10/n) solution from the textbook says 10
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lim as n approaches infinity sin(10/n)/(1/n) is how i would rewrite it. usually if it was sin(1/n)/(1/n) then i can use x=1/n let n approach infinity would mean x approaches zero since sin(x)/x as x approaches zero would equal 1 then sin(1/n)/(1/n) would be one is the method to solve this kind of the same as the one i have posted above?
@zepdrix
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