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what is the integral of 6^x
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6^x/log6+c
.. are are sure it isnt 6^(x+1) / x + 1 ?
and well + c lol
You only add 1 if it's 6x or something. But this is 6^x
ok.. care to explain how you got your answer?
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You need to use the formula!! integral of a^xdx=a^x/loga +c
yea i figured there was a formula lol thx alot!
if you want a slightly more intuitive way, remember that the derivative of \(a^x\) is \(a^x\ln a\), so if you integrate you can use u-substitution \[u=a^x\implies du=a^x\ln adx\implies a^xdx={du\over\ln a}\]
6^(x +1)divide by x + 1 plus C
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