what value completes the square for the expression? x^2-16x
Would it be 64 or -64?
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OpenStudy (otonogold):
@agent0smith
OpenStudy (otonogold):
I think its -64
OpenStudy (agent0smith):
To complete the square for
ax^2 + bx
find (b/2)^2
OpenStudy (agent0smith):
^notice the brackets.
OpenStudy (otonogold):
yea I see
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OpenStudy (agent0smith):
So what do you think it is?
OpenStudy (otonogold):
So Im incorrect on my answer btw?
OpenStudy (agent0smith):
^yes.
Easiest way is to ignore the negative, if b is negative.
That saves time with squaring ANY numbers, eg if you're squaring -24, just square 24 on a calculator, it saves time
OpenStudy (otonogold):
so it'll be 32?
OpenStudy (agent0smith):
Wait, how'd you get 32? Divide b by 2, then square it.
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OpenStudy (agent0smith):
(b/2)^2 is not the same as b^2/2
OpenStudy (otonogold):
the answer choices are:
-64
64
32
-32
Im 95% sure its -64
OpenStudy (otonogold):
I may be wrong though.
OpenStudy (agent0smith):
Let's go back to this. (b/2)^2
b is -16, right? So put that in there ^^
(-16/2)^2
(-8)^2
which is...
OpenStudy (otonogold):
64
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