Question

I need help understanding this problem. Graphing a linear equation (Image)

Answer 1

You can rewrite that as y=3/4x+3

Answer 2

it means the same thing, and that puts it in slope-intercept form. Do you know how to graph that?

Answer 3

And my username is a joke, don't worry XD

Answer 4

f(x) is the same thing as y,

Change it to y, then it'll be y = mx+b

y = 3/4x + 3

The y intercept is b ... in your problem, its 3

Plot it at (0,3)

The slope is m or 3/4 ... you would do rise/run

Go up from (0,3) to (0,6) and run to the left 4, which is (4,6)

Answer 5

I get clooosseee to where they want it but I keep being off?

;_;

Answer 6

?

Answer 7

I'm trying to follow the example that they gave me

x=0

g(x)= 3/4(0) so, that's zero. Then f(x)= 3/4x+3, ends up just being three
so I have (0,3)

Answer 8

thats wrong, you need that slope to draw the line, Rise / Run

In 3/4

Rise 3
Run 4