I must be tired or stupid, but this problem did confuse me.
Anyone kind enough to help?

Question

I must be tired or stupid, but this problem did confuse me.
Anyone kind enough to help?

solomonzelman · Answer

A population in place A is 50,000 in January 1, 2010. Every year the population in place A increases by 7%..
The population in place B is 70,000 in January 1, 2010. Every year the population in place A decreases by 5%.

at what year will the population of place A exceed the population in place B?

(slow typer, sorry)

anonymous · Answer

https://www.google.co.uk/#q=A+population+in+place+A+is+50%2C000+in+January+1%2C+2010.+Every+year+the+population+in+place+A+increases+by+7%25..

solomonzelman · Answer

smart   A S S ... I never thought of googling math questions.

the_fizicx99 · Answer

Wouldn't you use the geometric formula? f(x)=P(1+r)^x

blackops2luvr · Answer

BA BOOM

anonymous · Answer

Is the answer 18?

solomonzelman · Answer

I admit I suck at math, but not that much.

anonymous · Answer

Solve
$$
50000 (1+0.07)^t=70000 (1+.05)^t
$$
for t

the_fizicx99 · Answer

O_O noooo, not you

solomonzelman · Answer

I already did, and I got 3 as my answer for t.

solomonzelman · Answer

oops

solomonzelman · Answer

Actually after 4 years place A will be greater.

the_fizicx99 · Answer

Did you miss out that it says A decreases? 1.05 is a growth rate (above 0.99) or I'm i just confused ?

the_fizicx99 · Answer

am I *

solomonzelman · Answer

idk abt u, but ik I found the answer to my problem.

the_fizicx99 · Answer

._.  something like this? >.> idk either

solomonzelman · Answer

place B is decreasing by 7%. not increasing.

solomonzelman · Answer

Not by 7, by 5, but it is DEcreasing.

the_fizicx99 · Answer

I see where i might've gone wrong >.>

solomonzelman · Answer

okay, that was a good brain exercise, and thx everyone!

the_fizicx99 · Answer

-sigh- bo