Question

Hello Please help with this problem. Lost on the steps. Simplifying Radicals:
(m^1/4 n^1/2)^2 (m^2 n^3)^1/2

Answer 1

do you know what to do when the base is the same and exponents differ?

Answer 2

not really

Answer 3

http://www.biology.arizona.edu/biomath/tutorials/exponential/graphics/Law1.gif <--- you'd need for this one, the
rule 3, that is, distribute the outer exponent
and rule 1

Answer 4

okay I noticed the rules 1 and 3

Answer 5

would I use rule first

Answer 6

m*n=mn
m*n=m^2 n^3

Answer 7

http://mathb.in/12789

Answer 8

Not sure how to use that site

Answer 9

hmm ?

Answer 10

do you see the right-hand side part?

Answer 11

yes

Answer 12

how did you do all that with the codes

Answer 13

hehehe, well, I use an editor... so :)

Answer 14

so you see, same base, different exponents, rule 1 listed there
then you distribute the expression's exponenet

Answer 15

so would I end up with this
m*n=mn
m*n=m^2 n^3

Answer 16

hmm is that what you've got?

Answer 17

wait I forgot to square root

Answer 18

square root m n
square root m^2 n^3

Answer 19

hmmm so did you see the expression at the link?

Answer 20

which link

Answer 21

http://mathb.in/12789 <---

Answer 22

1/4m (9/4)n(7/2) following the link there I think this is the answer

Answer 23

http://mathb.in/12792 <--- look closely

Answer 24

the rule 1 from http://www.biology.arizona.edu/biomath/tutorials/exponential/graphics/Law1.gif
is used firstly

then rule 3

Answer 25

Okay, thank you I will work on studying this more. You have been a lot of help

Answer 26

yw