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Identify the center and radius of the circle (x+4)^2+(y-3)^2 = 16. a. center: (4,-2), r=4 b. center: (-4,2), r=4 c. center: (4, -2), r=16
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the standard form of a circle is \[(x -h)^2 + (y - k)^2 = r^2\] where (h, k) is the centre and r is the radius compare this to your equation and you'll get the centre and radius..
and it appears there may be a typo between your equation and answer choices... equation has y - 3 and anwers have 2
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