Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
OpenStudy (raffle_snaffle):
Power rule for the 1st integral
OpenStudy (raffle_snaffle):
power rule for the 2nd one and u substitution for the third
OpenStudy (raffle_snaffle):
U sub for 12 and power rule for 13
OpenStudy (raffle_snaffle):
You know power rule?
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (raffle_snaffle):
13 is power rule as well
OpenStudy (anonymous):
oh sorry I just need #12
OpenStudy (anonymous):
I don't know how to do it
OpenStudy (anonymous):
@eliassaab could you help me with #12? please?
OpenStudy (anonymous):
Distribute it out. x(x^2+3)=x^3+3x. Then apply power rule.
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
I don't know how...
OpenStudy (anonymous):
@ganeshie8
OpenStudy (anonymous):
@ranga
OpenStudy (anonymous):
help??
OpenStudy (ranga):
Integral of x^n is x^(n+1) / (n+1) + C
For example: #9 is integrate x^1/3.
It is x^(1/3+1) / (1/3+1) + C = 3/4 * x^(4/3) + C
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
so I am doing #12 so that would make it x^(3+1)/(3+1)+C= ??
OpenStudy (ranga):
First multiply x(x^2 + 3).
x(x^2 + 3) = x^3 + 3x
Now integrate each term. First x^3 and then 3x
x^4/4 + 3x^2/2 + C
OpenStudy (anonymous):
that goes after the = sign on the integrate i put above right?
OpenStudy (ranga):
For problem 12, in the Rewrite column, put: integral (x^3 + 3x)dx
In the Integrate column put: x^4/4 + 3x^2/2 + C
You can put the same value as the previous column or you can simplify it as:
x^4/4 + 6x^2/4 + C = x^2/4(x^2 + 6) + C and put x^2/4(x^2 + 6) + C in the last column.
OpenStudy (anonymous):
thank you very much
Still Need Help?
Join the QuestionCove community and study together with friends!