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Mathematics 21 Online
OpenStudy (anonymous):

Calculus help? Integral?

OpenStudy (anonymous):

OpenStudy (raffle_snaffle):

Power rule for the 1st integral

OpenStudy (raffle_snaffle):

power rule for the 2nd one and u substitution for the third

OpenStudy (raffle_snaffle):

U sub for 12 and power rule for 13

OpenStudy (raffle_snaffle):

You know power rule?

OpenStudy (raffle_snaffle):

13 is power rule as well

OpenStudy (anonymous):

oh sorry I just need #12

OpenStudy (anonymous):

I don't know how to do it

OpenStudy (anonymous):

@eliassaab could you help me with #12? please?

OpenStudy (anonymous):

Distribute it out. x(x^2+3)=x^3+3x. Then apply power rule.

OpenStudy (anonymous):

I don't know how...

OpenStudy (anonymous):

@ganeshie8

OpenStudy (anonymous):

@ranga

OpenStudy (anonymous):

help??

OpenStudy (ranga):

Integral of x^n is x^(n+1) / (n+1) + C For example: #9 is integrate x^1/3. It is x^(1/3+1) / (1/3+1) + C = 3/4 * x^(4/3) + C

OpenStudy (anonymous):

so I am doing #12 so that would make it x^(3+1)/(3+1)+C= ??

OpenStudy (ranga):

First multiply x(x^2 + 3). x(x^2 + 3) = x^3 + 3x Now integrate each term. First x^3 and then 3x x^4/4 + 3x^2/2 + C

OpenStudy (anonymous):

that goes after the = sign on the integrate i put above right?

OpenStudy (ranga):

For problem 12, in the Rewrite column, put: integral (x^3 + 3x)dx In the Integrate column put: x^4/4 + 3x^2/2 + C You can put the same value as the previous column or you can simplify it as: x^4/4 + 6x^2/4 + C = x^2/4(x^2 + 6) + C and put x^2/4(x^2 + 6) + C in the last column.

OpenStudy (anonymous):

thank you very much

OpenStudy (ranga):

You are welcome.

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